1986 AIME Problem 3

Attempt Problem 3 of the 1986 AIME below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1986 AIME solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

3.

If tan⁡x+tan⁡y=25\tan x+\tan y=25 and cot⁡x+cot⁡y=30,\cot x+\cot y=30, what is tan⁡(x+y)?\tan(x+y)?
Answer: 150
Concepts:algebraic manipulationtrigonometric identity
Small hint:
Express the sum of the cotangents using tan⁡x\tan x and tan⁡y\tan y
Big hint:
Use the tangent addition formula after finding tan⁡xtan⁡y\tan x\tan y
Solution:
Since cot⁡x+cot⁡y=tan⁡x+tan⁡ytan⁡xtan⁡y, \cot x+\cot y =\frac{\tan x+\tan y}{\tan x\tan y}, the given equations yield tan⁡xtan⁡y=2530=56.\tan x\tan y=\frac{25}{30}=\frac{5}{6}. Therefore tan⁡(x+y)=tan⁡x+tan⁡y1−tan⁡xtan⁡y=251−56=150. \begin{aligned} \tan(x+y) &=\frac{\tan x+\tan y} {1-\tan x\tan y}\\ &=\frac{25}{1-\frac56}\\ &=150. \end{aligned}
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