1986 AIME Problem 6

Attempt Problem 6 of the 1986 AIME below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1986 AIME solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

6.

The pages of a book are numbered 11 through n.n. When the page numbers of the book were added, one of the page numbers was mistakenly added twice, resulting in an incorrect sum of 1986.1986. What was the number of the page that was added twice?
Answer: 33
Concepts:bounding to limit casestriangular number
Small hint:
Compare 19861986 with consecutive triangular numbers
Big hint:
The excess over 1+2+⋯+n1+2+\cdots+n is the repeated page number
Solution:
Consecutive triangular numbers around 19861986 are 62⋅632=1953,63⋅642=2016. \begin{aligned} \frac{62\cdot63}{2}&=1953,\\ \frac{63\cdot64}{2}&=2016. \end{aligned} Hence the book has 6262 pages, and the extra summand is 1986−1953=33,1986-1953=33, which is indeed a valid page number.
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