1988 AIME Problem 13

Attempt Problem 13 of the 1988 AIME below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1988 AIME solutions, or check the answer key.

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13.

Find aa if aa and bb are integers such that x2−x−1x^2-x-1 is a factor of ax17+bx16+1.ax^{17}+bx^{16}+1.
Answer: 987
Concepts:polynomialFibonaccisystem of equations
Small hint:
Modulo x2−x−1,x^2-x-1, powers satisfy xn=Fnx+Fn−1x^n=F_nx+F_{n-1}
Big hint:
Set both coefficients of the linear remainder equal to zero and use Cassini’s identity
Solution:
Modulo x2−x−1,x^2-x-1, the relation x2=x+1x^2=x+1 gives xn=Fnx+Fn−1.x^n=F_nx+F_{n-1}. Hence the remainder is r(x)=(1597a+987b)x+(987a+610b+1).\begin{aligned}r(x)={}&(1597a+987b)x\\&+(987a+610b+1).\end{aligned} Both coefficients must vanish. The determinant of the coefficient matrix is 1597(610)−9872=11597(610)-987^2=1 by Cassini’s identity. Cramer’s rule then gives a=987.a=987.
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