1992 AIME Problem 8

Attempt Problem 8 of the 1992 AIME below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1992 AIME solutions, or check the answer key.

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8.

For any sequence of real numbers A=(a1,a2,a3,…),A=(a_1,a_2,a_3,\ldots), define ΔA\Delta A to be the sequence (a2−a1,a3−a2,a4−a3,…),(a_2-a_1,a_3-a_2,a_4-a_3,\ldots), whose nnth term is an+1−an.a_{n+1}-a_n. Suppose that all of the terms of the sequence Δ(ΔA)\Delta(\Delta A) are 1,1, and that a19=a92=0.a_{19}=a_{92}=0. Find a1.a_1.
Answer: 819
Concepts:quadraticrecursionfactoring
Small hint:
A sequence with constant second difference 11 is given by a quadratic with leading coefficient 12\frac{1}{2}
Big hint:
Use the two zero terms to write the quadratic in factored form
Solution:
A quadratic sequence with second difference 11 has leading coefficient 12.\frac{1}{2}. Since its values vanish at indices 1919 and 92,92, an=12(n−19)(n−92).a_n=\frac12(n-19)(n-92). Therefore a1=12(−18)(−91)=819.a_1=\frac12(-18)(-91)=819.
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