1950 AMC 12 Problem 45

Attempt Problem 45 of the 1950 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1950 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

45.

The number of diagonals that can be drawn in a polygon of 100100 sides is:
48504850
49504950
99009900
9898
88008800
Answer: A
Concepts:diagonalcombinations
Small hint:
Every pair of vertices determines a segment
Big hint:
Subtract the 100100 sides from the (1002)\binom{100}{2} vertex pairs
Solution:
There are (1002)\binom{100}{2} segments joining pairs of vertices. Exactly 100100 of these are sides, so the number of diagonals is (1002)−100=4950−100=4850. \begin{aligned} \binom{100}{2}-100 &=4950-100\\ &=4850. \end{aligned}
Thus, the correct answer is A.
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