1951 AMC 12 Problem 16

Attempt Problem 16 of the 1951 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1951 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

16.

If in applying the quadratic formula to a quadratic equation f(x)=ax2+bx+c=0, f(x)=ax^2+bx+c=0, it happens that c=b24a,c=\dfrac{b^2}{4a}, then the graph of y=f(x)y=f(x) will certainly:
Have a maximum
Have a minimum
Be tangent to the xx-axis
Be tangent to the yy-axis
Lie in one quadrant only
Answer: C
Concepts:quadratictangent line
Small hint:
Substitute the condition into the discriminant b2−4acb^2-4ac
Big hint:
A quadratic with one repeated real root touches the horizontal axis once
Solution:
The condition gives b2−4ac=b2−4a(b24a)=0. b^2-4ac=b^2-4a\left(\frac{b^2}{4a}\right)=0. Hence the quadratic has a repeated real root, so its parabola is tangent to the xx-axis.
Thus, the correct answer is C.
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