1952 AMC 12 Problem 42

Attempt Problem 42 of the 1952 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1952 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

42.

Let DD represent a repeating decimal. If PP denotes the rr figures of DD which do not repeat themselves, and QQ denotes the ss figures which do repeat themselves, then the incorrect expression is:
D=0.PQQQ…D=0.PQQQ\ldots
10rD=P.QQQ…10^rD=P.QQQ\ldots
10r+sD=PQ.QQQ…10^{r+s}D=PQ.QQQ\ldots
10r(10s−1)D=Q(P−1)10^r(10^s-1)D=Q(P-1)
10r⋅102sD=10^r\cdot10^{2s}D= PQQ.QQQ…PQQ.QQQ\ldots
Answer: D
Concepts:repeating decimalplace valuealgebraic manipulation
Small hint:
Shift the decimal point first past the rr nonrepeating digits and then past one block of ss repeating digits
Big hint:
Subtract 10rD10^rD from 10r+sD10^{r+s}D and compare the result with choice D
Solution:
After shifting past the nonrepeating block, 10rD=P.QQQ…, 10^rD=P.QQQ\ldots, and after shifting one repeating block farther, 10r+sD=PQ.QQQ…. 10^{r+s}D=PQ.QQQ\ldots. Subtracting yields the standard relation 10r(10s−1)D=P(10s−1)+Q. \begin{gathered} 10^r(10^s-1)D \\ =P(10^s-1)+Q. \end{gathered} This is not Q(P−1),Q(P-1), as stated in choice D.
Thus, the incorrect expression, and hence the correct answer, is D.
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