1953 AMC 12 Problem 49

Attempt Problem 49 of the 1953 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1953 AMC 12 solutions, or check the answer key.

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49.

The coordinates of A,A, BB and CC are (5,5),(5,5), (2,1)(2,1) and (0,k)(0,k) respectively. The value of kk that makes AC‾+BC‾\overline{AC}+\overline{BC} as small as possible is:
33
4124\dfrac12
3673\dfrac67
4564\dfrac56
2172\dfrac17
Answer: E
Concepts:reflectionshortest pathcoordinate geometry
Small hint:
Reflect BB across the yy-axis so that BCBC becomes the distance from CC to the reflected point
Big hint:
The shortest broken path occurs where the straight line from AA to the reflected point meets the yy-axis
Solution:
Reflect B=(2,1)B=(2,1) across the yy-axis to B′=(−2,1).B'=(-2,1). For CC on the yy-axis, BC=B′C,BC=B'C, so AC+BCAC+BC is minimized when A,C,B′A,C,B' are collinear. The line from A=(5,5)A=(5,5) to B′=(−2,1)B'=(-2,1) has slope 47.\frac{4}{7}. At x=0,x=0, its height is 5−47(5)=157=217. 5-\frac47(5)=\frac{15}{7}=2\frac17. Hence k=157.k=\frac{15}{7}.
Thus, the correct answer is E.
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