1970 AMC 12 Problem 27

Attempt Problem 27 of the 1970 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1970 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

27.

In a triangle, the area is numerically equal to the perimeter. What is the radius of the inscribed circle?
22
33
44
55
66
Answer: A
Concepts:incircle, incenter, and inradiustriangle areaperimeter
Small hint:
Express the area in terms of the inradius and semiperimeter
Big hint:
Use K=rsK=rs and perimeter =2s=2s
Solution:
If rr is the inradius and ss the semiperimeter, the triangle’s area is K=rs.K=rs. Its perimeter is 2s.2s. The given equality yields rs=2s. rs=2s. Since s>0,s\gt0, we obtain r=2.r=2.
Therefore, the correct answer is A.
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