1950 AMC 12 Problem 33

Attempt Problem 33 of the 1950 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1950 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

33.

The number of circular pipes with an inside diameter of 11 inch which will carry the same amount of water as a pipe with an inside diameter of 66 inches is:
6π6\pi
66
1212
3636
36π36\pi
Answer: D
Concepts:circle areapower scaling of length, area, and volume
Small hint:
Water-carrying capacity is proportional to cross-sectional area
Big hint:
Circular area scales as the square of the diameter
Solution:
The ratio of the diameters is 6:1,6:1, so the ratio of cross-sectional areas is 62:12=36:1. 6^2:1^2=36:1. Thus 3636 of the smaller pipes have the same total cross-sectional area as the larger pipe.
Thus, the correct answer is D.
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