1952 AMC 12 Problem 38

Attempt Problem 38 of the 1952 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1952 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

38.

The area of a trapezoidal field is 14001400 square yards. Its altitude is 5050 yards. Find the two bases, if the number of yards in each base is an integer divisible by 8.8. The number of solutions to this problem is:
None
One
Two
Three
More than three
Answer: D
Concepts:trapezoiddivisibilitybasic counting
Small hint:
Use the trapezoid area formula to find the sum of the two bases
Big hint:
List the unordered pairs of positive multiples of 88 with that sum
Solution:
If the bases are b1,b2,b_1,b_2, then 1400=12(b1+b2)(50), 1400=\frac12(b_1+b_2)(50), so b1+b2=56.b_1+b_2=56. The unordered positive pairs of multiples of 88 are (8,48),(16,40),(24,32). (8,48),\quad(16,40),\quad(24,32). There are three solutions.
Thus, the correct answer is D.
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