1962 AMC 12 Problem 38

Attempt Problem 38 of the 1962 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1962 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

38.

The population of Nosuch Junction at one time was a perfect square. Later, with an increase of 100,100, the population was one more than a perfect square. Now, with an additional increase of 100,100, the population is again a perfect square.
The original population is a multiple of:
33
77
99
1111
1717
Answer: B
Concepts:difference of squaresperfect squarefactorsystematic listing
Small hint:
Write the populations as a2,a^2, b2+1,b^2+1, and c2c^2
Big hint:
From b2−a2=99,b^2-a^2=99, test the positive factor pairs of 9999, then impose c2−a2=200c^2-a^2=200
Solution:
Let the original population be a2.a^2. Then b2−a2=99,c2−a2=200. \begin{aligned} b^2-a^2&=99,\\ c^2-a^2&=200. \end{aligned} From (b−a)(b+a)=99,(b-a)(b+a)=99, the positive possibilities for aa are 49,49, 15,15, and 1.1. Checking the second condition, only a=49a=49 works, since 492+200=2601=512. 49^2+200=2601=51^2. The population is 492=74,49^2=7^4, a multiple of 7.7.
Thus, the correct answer is B.
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