1954 AMC 12 Problem 37

Attempt Problem 37 of the 1954 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1954 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

37.

Given triangle PQRPQR with RS‾\overline{RS} bisecting ∠R,\angle R, PQ‾\overline{PQ} extended to D,D, and ∠n\angle n a right angle, then:
∠m=12(∠p−∠q)\angle m=\dfrac12(\angle p-\angle q)
∠m=12(∠p+∠q)\angle m=\dfrac12(\angle p+\angle q)
∠d=12(∠q+∠p)\angle d=\dfrac12(\angle q+\angle p)
∠d=12∠m\angle d=\dfrac12\angle m
none of these is correct
Answer: B
Concepts:angle bisectorangle chasingangle sum
Small hint:
The bisected angle at RR measures 180∘−∠p−∠q180^\circ-\angle p-\angle q before it is halved
Big hint:
Since the transversal is perpendicular to the angle bisector, ∠m\angle m complements half of ∠R\angle R
Solution:
The angle at RR is 180∘−∠p−∠q. 180^\circ-\angle p-\angle q. Because RS‾\overline{RS} bisects this angle, the angle between PR‾\overline{PR} and RS‾\overline{RS} is 90∘−12(∠p+∠q). 90^\circ-\frac12(\angle p+\angle q). The line forming ∠m\angle m is perpendicular to RS‾,\overline{RS}, so ∠m=12(∠p+∠q). \angle m=\frac12(\angle p+\angle q).
Thus, the correct answer is B.
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