1956 AMC 12 Problem 37

Attempt Problem 37 of the 1956 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1956 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

37.

On a map whose scale is 400400 miles to an inch and a half, a certain estate is represented by a rhombus having a 60∘60^\circ angle. The diagonal opposite 60∘60^\circ is 316\dfrac3{16} in. The area of the estate in square miles is:
25003\dfrac{2500}{\sqrt3}
12503\dfrac{1250}{\sqrt3}
12501250
562532\dfrac{5625\sqrt3}{2}
125031250\sqrt3
Answer: E
Concepts:map scalerhombusequilateral trianglesarea
Small hint:
In a 60∘60^\circ rhombus, the shorter diagonal equals the side length
Big hint:
The scale is 8003\frac{800}{3} miles per inch, so convert the 316\frac{3}{16}-inch side before finding area
Solution:
The diagonal opposite the 60∘60^\circ angle divides the rhombus into two equilateral triangles, so its length equals the rhombus side. The map scale is 8003\frac{800}{3} miles per inch, hence the actual side length is 316⋅8003=50 \frac3{16}\cdot\frac{800}{3}=50 miles. Therefore the rhombus area is 502sin⁡60∘=2500⋅32=12503. \begin{aligned} 50^2\sin60^\circ &=2500\cdot\frac{\sqrt3}{2}\\ &=1250\sqrt3. \end{aligned}
Thus, the correct answer is E.
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