1957 AMC 12 Problem 4

Attempt Problem 4 of the 1957 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1957 AMC 12 solutions, or check the answer key.

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4.

The first step in finding the product (3x+2)(x−5)(3x+2)(x-5) by use of the distributive property in the form a(b+c)=ab+aca(b+c)=ab+ac is:
3x2−13x−103x^2-13x-10
3x(x−5)+2(x−5)3x(x-5)+2(x-5)
(3x+2)x+(3x+2)(−5)(3x+2)x+(3x+2)(-5)
3x2−17x−103x^2-17x-10
3x2+2x−15x−103x^2+2x-15x-10
Answer: C
Concepts:distributive propertyalgebraic manipulation
Small hint:
Match the second factor with b+cb+c in the stated form
Big hint:
Take a=3x+2,a=3x+2, b=x,b=x, and c=−5c=-5
Solution:
Using the property in precisely the stated form, set a=3x+2,a=3x+2, b=x,b=x, and c=−5.c=-5. Then (3x+2)(x−5)=(3x+2)x+(3x+2)(−5). \begin{gathered} (3x+2)(x-5)\\ =(3x+2)x+(3x+2)(-5). \end{gathered}
Thus, the correct answer is C.
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