1960 AMC 12 Problem 35

Attempt Problem 35 of the 1960 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1960 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

35.

From point PP outside a circle, with a circumference of 1010 units, a tangent is drawn. Also from PP a secant is drawn dividing the circle into unequal arcs with lengths mm and n.n. It is found that t,t, the length of the tangent, is the mean proportional between mm and n.n. If mm and tt are integers, then tt may have the following number of values:
zero
one
two
three
infinitely many
Answer: C
Concepts:ratio and proportionperfect squarearc
Small hint:
Use m+n=10m+n=10 and t2=mnt^2=mn
Big hint:
Test the integer values m=1,2,…,9,m=1,2,\ldots,9, excluding equal arcs
Solution:
The arc lengths satisfy m+n=10,m+n=10, while the mean-proportional condition gives t2=mn=m(10−m). t^2=mn=m(10-m). For integral mm from 11 through 9,9, the possible products, up to symmetry, are 9,9, 16,16, 21,21, 24,24, and 25.25. The last comes from equal arcs m=n=5m=n=5 and is excluded. The remaining squares give t=3t=3 and t=4,t=4, two values.
Thus, the correct answer is C.
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