1962 AMC 12 Problem 20

Attempt Problem 20 of the 1962 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1962 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

20.

The angles of a pentagon are in arithmetic progression. One of the angles, in degrees, must be:
108108
9090
7272
5454
3636
Answer: A
Concepts:angle sumarithmetic sequence
Small hint:
Five terms in arithmetic progression have their middle term equal to their average
Big hint:
The interior angles of a pentagon sum to 540∘540^\circ
Solution:
The average of the five angles is 540∘5=108∘.\frac{540^\circ}{5}=108^\circ. For five terms in arithmetic progression, the middle term equals the average, so one angle must be 108∘.108^\circ.
Thus, the correct answer is A.
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