1963 AMC 12 Problem 40

Attempt Problem 40 of the 1963 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1963 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

40.

If xx is a number satisfying the equation x+93−x−93=3,\sqrt[3]{x+9}-\sqrt[3]{x-9}=3, then x2x^2 is between:
5555 and 6565
6565 and 7575
7575 and 8585
8585 and 9595
9595 and 105105
Answer: C
Concepts:radicalsum and difference of cubessymmetry (algebra)
Small hint:
Set u=x+93u=\sqrt[3]{x+9} and v=x−93v=\sqrt[3]{x-9}
Big hint:
Use both u−v=3u-v=3 and u3−v3=18u^3-v^3=18 to find uvuv
Solution:
Let u=x+93u=\sqrt[3]{x+9} and v=x−93.v=\sqrt[3]{x-9}. Then u−v=3u-v=3 and 18=u3−v3=(u−v)(u2+uv+v2), \begin{aligned} 18&=u^3-v^3\\ &=(u-v)(u^2+uv+v^2), \end{aligned} so u2+uv+v2=6.u^2+uv+v^2=6. Comparing with (u−v)2=9(u-v)^2=9 gives uv=−1.uv=-1. Hence (u+v)2=5.(u+v)^2=5. Cubing 2u=3±52u=3\pm\sqrt5 gives x=±45,x=\pm4\sqrt5, and either way x2=80,x^2=80, between 7575 and 85.85.
Therefore, the correct answer is C.
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