1968 AMC 12 Problem 24

Attempt Problem 24 of the 1968 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1968 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

24.

A painting 18′′×24′′18''\times24'' is to be placed into a wooden frame with the longer dimension vertical. The wood at the top and bottom is twice as wide as the wood on the sides. If the frame area equals that of the painting itself, the ratio of the smaller to the larger dimension of the framed painting is:
1:31:3
1:21:2
2:32:3
3:43:4
1:11:1
Answer: C
Concepts:rectangleareaquadraticratio and proportion
Small hint:
Let each side strip have width xx, so each top strip has width 2x2x
Big hint:
Set the outside area equal to twice 18⋅2418\cdot24
Solution:
The outside dimensions are 18+2x18+2x and 24+4x.24+4x. Since the frame area equals the painting area, (18+2x)(24+4x)=2(18)(24).(18+2x)(24+4x)=2(18)(24). This gives x2+15x−54=0,x^2+15x-54=0, so x=3.x=3. The dimensions are 2424 and 36,36, with ratio 2:3.2:3.
Therefore, the correct answer is C.
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