1971 AMC 12 Problem 14

Attempt Problem 14 of the 1971 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1971 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

14.

The number 248−12^{48}-1 is exactly divisible by two numbers between 6060 and 70.70. These numbers are:
61,61, 6363
61,61, 6565
63,63, 6565
63,63, 6767
67,67, 6969
Answer: C
Concepts:factoringexponentdivisibility
Small hint:
Use the fact that 2m−12^m-1 divides 2n−12^n-1 whenever nn is divisible by mm
Big hint:
Recognize 63=26−163=2^6-1 and that 212−12^{12}-1 is divisible by 6565
Solution:
Because 4848 is divisible by 6,6, the number 248−1 2^{48}-1 is divisible by 63=26−1.63=2^6-1. Also 212−1=4095=63⋅65,2^{12}-1=4095=63\cdot65, and 4848 is divisible by 12,12, so 248−12^{48}-1 is divisible by 65.65. Thus the two numbers are 6363 and 65.65.
Therefore, the correct answer is C.
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