1973 AMC 12 Problem 3

Attempt Problem 3 of the 1973 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1973 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

3.

The stronger Goldbach conjecture states that any even integer greater than 77 can be written as the sum of two different prime numbers. For such representations of the even number 126,126, the largest possible difference between the two primes is
Note: The regular Goldbach conjecture states that any even integer greater than 33 is expressible as a sum of two primes. Neither this conjecture nor the stronger version has been settled.
112112
100100
9292
8888
8080
Answer: B
Concepts:primeoptimizationsystematic listing
Small hint:
For a fixed sum, maximize the difference by minimizing the smaller prime
Big hint:
Test the primes 3,3, 5,5, 7,7, 11,11, 13,13, …\ldots until the complement to 126126 is prime
Solution:
For primes p<qp\lt q with p+q=126,p+q=126, the difference q−p=126−2pq-p=126-2p is largest when pp is as small as possible. The complements of 3,3, 5,5, 7,7, and 1111 are 123,123, 121,121, 119,119, and 115,115, none prime. For p=13,p=13, the complement is 113,113, which is prime. Thus the largest difference is 113−13=100. 113-13=100.
Therefore, the correct answer is B.
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