1982 AMC 12 Problem 22

Attempt Problem 22 of the 1982 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1982 AMC 12 solutions, or check the answer key.

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22.

In a narrow alley of width ww a ladder of length aa is placed with its foot at a point PP between the walls. Resting against one wall at Q,Q, a distance kk above the ground, the ladder makes a 45∘45^\circ angle with the ground. Resting against the other wall at R,R, a distance hh above the ground, the ladder makes a 75∘75^\circ angle with the ground. The width ww is equal to
aa
RQRQ
kk
h+k2\frac{h+k}{2}
hh
Answer: E
Concepts:trigonometryright triangletrigonometric identity
Small hint:
Express the two horizontal portions of the alley using cosines
Big hint:
Compare cos⁡75∘+cos⁡45∘\cos75^\circ+\cos45^\circ with sin⁡75∘\sin75^\circ
Solution:
The horizontal distances from PP to the walls are acos⁡75∘a\cos75^\circ and acos⁡45∘,a\cos45^\circ, so w=a(cos⁡75∘+cos⁡45∘).w=a(\cos75^\circ+\cos45^\circ). The sum-to-product identity gives cos⁡75∘+cos⁡45∘=sin⁡75∘.\cos75^\circ+\cos45^\circ=\sin75^\circ. Since h=asin⁡75∘,h=a\sin75^\circ, w=h.w=h.
Therefore, the correct answer is E.
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