1950 AMC 12 Problem 22

Attempt Problem 22 of the 1950 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1950 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

22.

Successive discounts of 10%10\% and 20%20\% are equivalent to a single discount of:
30%30\%
15%15\%
72%72\%
28%28\%
None of these
Answer: D
Concepts:percentage
Small hint:
Apply both discounts to a price of 100100
Big hint:
After the first discount, the second discount is taken from 90,90, not from 100100
Solution:
Starting from a price of 100,100, the first discount leaves 90.90. The second discount leaves 0.8(90)=72.0.8(90)=72. The total reduction is therefore 100−72=28,100-72=28, or 28%.28\%.
Thus, the correct answer is D.
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