1950 AMC 12 Problem 5

Attempt Problem 5 of the 1950 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1950 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

5.

If five geometric means are inserted between 88 and 5832,5832, the fifth term in the geometric series is:
648648
832832
11681168
19441944
None of these answers
Answer: A
Concepts:geometric sequenceexponent
Small hint:
Inserting five means makes the given numbers the first and seventh terms
Big hint:
If the common ratio is q,q, then 8q6=58328q^6=5832
Solution:
There are six common-ratio steps from the first term 88 to the seventh term 5832.5832. Thus q6=58328=729=36, q^6=\frac{5832}{8}=729=3^6, so the positive common ratio is q=3.q=3. The fifth term is 8q4=8⋅34=648. 8q^4=8\cdot3^4=648.
Thus, the correct answer is A.
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