1965 AMC 12 Problem 5

Attempt Problem 5 of the 1965 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1965 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

5.

When the repeating decimal 0.363636…0.363636\ldots is written in simplest fractional form, the sum of the numerator and denominator is:
1515
4545
114114
135135
150150
Answer: A
Concepts:repeating decimalfraction
Small hint:
Multiply the decimal by 100100 and subtract the original number
Big hint:
Simplify 3699\frac{36}{99}
Solution:
Let z=0.363636….z=0.363636\ldots. Then 100z−z=36,100z-z=36, so z=3699=411.z=\frac{36}{99}=\frac{4}{11}. The requested sum is 4+11=15.4+11=15.
Therefore, the correct answer is A.
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