1951 AMC 12 Problem 31

Attempt Problem 31 of the 1951 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1951 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

31.

A total of 2828 handshakes was exchanged at the conclusion of a party. Assuming that each participant was equally polite toward all the others, the number of people present was:
1414
2828
5656
88
77
Answer: D
Concepts:counting pairsquadratic
Small hint:
With nn people, each unordered pair shakes hands once
Big hint:
Solve (n2)=28\binom n2=28
Solution:
With nn people the number of handshakes is (n2)=n(n−1)2. \binom n2=\frac{n(n-1)}2. Thus n(n−1)=56,n(n-1)=56, and the positive solution is n=8.n=8.
Thus, the correct answer is D.
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