1956 AMC 12 Problem 31

Attempt Problem 31 of the 1956 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1956 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

31.

In our number system the base is ten. If the base were changed to four you would count as follows: 1,1, 2,2, 3,3, 10,10, 11,11, 12,12, 13,13, 20,20, 21,21, 22,22, 23,23, 30,30, …\ldots The twentieth number would be:
2020
3838
4444
104104
110110
Answer: E
Concepts:base fourplace valuenumber representation
Small hint:
The twentieth positive number represents the ordinary value 2020
Big hint:
Divide 2020 successively by 4,4, or express it using the place values 16,16, 4,4, and 11
Solution:
The twentieth positive integer has ordinary value 20.20. Since 20=1⋅42+1⋅4+0, 20=1\cdot4^2+1\cdot4+0, its base-four representation is 110.110.
Thus, the correct answer is E.
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