1951 AMC 12 Problem 7

Attempt Problem 7 of the 1951 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1951 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

7.

An error of 0.02′′0.02'' is made in the measurement of a line 10′′10'' long, while an error of only 0.2′′0.2'' is made in a measurement of a line 100′′100'' long. In comparison with the relative error of the first measurement, the relative error of the second measurement is:
Greater by 0.180.18
The same
Less
1010 times as great
Correctly described by both (A)(A) and (D)(D)
Answer: B
Concepts:ratio and proportiondecimal
Small hint:
Relative error is the absolute error divided by the measured length
Big hint:
Compare 0.0210\frac{0.02}{10} with 0.2100\frac{0.2}{100}
Solution:
The two relative errors are 0.0210=0.002\frac{0.02}{10}=0.002 and 0.2100=0.002.\frac{0.2}{100}=0.002. They are equal.
Thus, the correct answer is B.
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