1952 AMC 12 Problem 32

Attempt Problem 32 of the 1952 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1952 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

32.

KK takes 3030 minutes less time than MM to travel a distance of 3030 miles. KK travels 13\dfrac13 mile per hour faster than M.M. If xx is KK’s rate of speed in miles per hour, then KK’s time for the distance is:
x+1330\dfrac{x+\frac{1}{3}}{30}
x−1330\dfrac{x-\frac{1}{3}}{30}
30x+13\dfrac{30}{x+\frac{1}{3}}
30x\dfrac{30}{x}
x30\dfrac{x}{30}
Answer: D
Concepts:distance rate and timerate
Small hint:
Use the basic relation time=distancerate\text{time}=\frac{\text{distance}}{\text{rate}}
Big hint:
The question asks only for KK’s time, and both KK’s distance and rate are already given
Solution:
For K,K, the distance is 3030 miles and the rate is xx miles per hour. Thus time=distancerate=30x hours. \text{time}=\frac{\text{distance}}{\text{rate}} =\frac{30}{x}\text{ hours}. The comparison with MM is not needed for this expression.
Thus, the correct answer is D.
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