1961 AMC 12 Problem 32

Attempt Problem 32 of the 1961 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1961 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

32.

A regular polygon of nn sides is inscribed in a circle of radius R.R. The area of the polygon is 3R2.3R^2. Then nn equals:
88
1010
1212
1515
1818
Answer: C
Concepts:regular polygontrigonometryarea decomposition
Small hint:
Divide the polygon into nn congruent triangles with vertex at the center
Big hint:
Use area 12nR2sin⁡(360∘n)\frac12nR^2\sin(\frac{360^\circ}{n}) and test the choices
Solution:
The polygon’s area is n2R2sin⁡360∘n. \frac n2R^2\sin\frac{360^\circ}{n}. For n=12,n=12, this becomes 6R2sin⁡30∘=3R2, 6R^2\sin30^\circ=3R^2, as required.
Therefore, the correct answer is C.
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