1954 AMC 12 Problem 20

Attempt Problem 20 of the 1954 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1954 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

20.

The equation x3+6x2+11x+6=0x^3+6x^2+11x+6=0 has:
no negative real roots
no positive real roots
no real roots
11 positive and 22 negative roots
22 positive and 11 negative root
Answer: B
Concepts:polynomialfactoringzero product property
Small hint:
Test the small negative integers suggested by the constant term
Big hint:
The polynomial factors as (x+1)(x+2)(x+3)(x+1)(x+2)(x+3)
Solution:
The polynomial factors as x3+6x2+11x+6=(x+1)(x+2)(x+3). \begin{gathered} x^3+6x^2+11x+6\\ =(x+1)(x+2)(x+3). \end{gathered} Its roots are −1,−2,−3,-1,-2,-3, so it has no positive real roots.
Thus, the correct answer is B.
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