1954 AMC 12 Problem 4

Attempt Problem 4 of the 1954 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1954 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

4.

If the Highest Common Divisor of 64326432 and 132132 is diminished by 8,8, it will equal:
−6-6
66
−2-2
33
44
Answer: E
Concepts:greatest common divisorprime factorizationwhole number operations
Small hint:
Use the Euclidean algorithm or factor the two numbers
Big hint:
Their greatest common divisor is 1212
Solution:
The Euclidean algorithm gives gcd⁡(6432,132)=12. \gcd(6432,132)=12. Diminishing this by 88 gives 12−8=4.12-8=4.
Thus, the correct answer is E.
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