1957 AMC 12 Problem 14

Attempt Problem 14 of the 1957 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1957 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

14.

If y=x2−2x+1y=\sqrt{x^2-2x+1} +x2+2x+1,{}+\sqrt{x^2+2x+1}, then yy is:
2x2x
2(x+1)2(x+1)
00
∣x−1∣+∣x+1∣|x-1|+|x+1|
none of these
Answer: D
Concepts:radicalperfect squareabsolute value
Small hint:
Factor each radicand as a perfect square
Big hint:
For real u,u, u2=∣u∣\sqrt{u^2}=|u|
Solution:
The two radicands are (x−1)2(x-1)^2 and (x+1)2.(x+1)^2. Hence y=(x−1)2+(x+1)2=∣x−1∣+∣x+1∣. \begin{aligned} y&=\sqrt{(x-1)^2}\\ &\quad+\sqrt{(x+1)^2}\\ &=|x-1|+|x+1|. \end{aligned}
Thus, the correct answer is D.
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