1957 AMC 12 Problem 30

Attempt Problem 30 of the 1957 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1957 AMC 12 solutions, or check the answer key.

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30.

The sum of the squares of the first nn positive integers is given by the expression n(n+c)(2n+k)6,\dfrac{n(n+c)(2n+k)}6, if cc and kk are, respectively:
11 and 22
33 and 55
22 and 22
11 and 11
22 and 11
Answer: D
Concepts:sum of first n squarespolynomial
Small hint:
Compare the expression with the standard sum-of-squares formula
Big hint:
Alternatively, substitute n=1n=1 and n=2n=2 to obtain two equations
Solution:
The standard formula is 12+22+⋯+n2=n(n+1)6⋅(2n+1). \begin{aligned} 1^2+2^2+\cdots+n^2 &=\frac{n(n+1)}6\\ &\quad\cdot(2n+1). \end{aligned} Therefore c=1c=1 and k=1.k=1.
Thus, the correct answer is D.
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