1964 AMC 12 Problem 38

Attempt Problem 38 of the 1964 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1964 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

38.

The sides PQPQ and PRPR of triangle PQRPQR are respectively of lengths 44 inches and 77 inches. The median PMPM is 3123\dfrac12 inches. Then QR,QR, in inches, is:
66
77
88
99
1010
Answer: D
Concepts:median (geometry)Stewart’s Theoremlaw of cosines
Small hint:
Use Apollonius’s theorem for the median to QRQR
Big hint:
Substitute PQ=4, PR=7, PM=72PQ=4,\ PR=7,\ PM=\frac{7}{2}
Solution:
Apollonius’s theorem gives QR2=2(42+72)−4(72)2=81. \begin{aligned} QR^2 &=2(4^2+7^2)-4\left(\frac72\right)^2\\ &=81. \end{aligned} Therefore QR=9.QR=9.
Thus, the correct answer is D.
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