1965 AMC 12 Problem 20

Attempt Problem 20 of the 1965 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1965 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

20.

For every nn the sum SnS_n of nn terms of an arithmetic progression is 2n+3n2.2n+3n^2. The rrth term is:
3r23r^2
3r2+2r3r^2+2r
6r−16r-1
5r+55r+5
6r+26r+2
Answer: C
Concepts:arithmetic sequencesummationalgebraic manipulation
Small hint:
The rrth term equals Sr−Sr−1S_r-S_{r-1}
Big hint:
Compute the difference of the two quadratic expressions
Solution:
The rrth term is the difference of consecutive partial sums. Substitution and simplification give Sr−Sr−1=6r−1.S_r-S_{r-1}=6r-1.
Therefore, the correct answer is C.
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