1967 AMC 12 Problem 24

Attempt Problem 24 of the 1967 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1967 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

24.

The number of solution-pairs in positive integers of the equation 3x+5y=5013x+5y=501 is:
3333
3434
3535
100100
none of these
Answer: A
Concepts:Diophantine Equationmodular arithmeticcounting integers in a range
Small hint:
Reduce the equation modulo 55 to find the form of xx
Big hint:
Count the positive values x=2+5kx=2+5k that leave y>0y\gt0
Solution:
Modulo 5,5, the equation gives 3x≡1,3x\equiv1, so x≡2(mod5).x\equiv2\pmod5. Write x=2+5k.x=2+5k. Then y=501−3x5=99−3k. y=\frac{501-3x}{5}=99-3k. Positivity requires k=0,1,…,32,k=0,1,\ldots,32, giving 3333 pairs.
Therefore, the correct answer is A.
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