1971 AMC 12 Problem 6

Attempt Problem 6 of the 1971 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1971 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

6.

Let ∗* be a symbol denoting the binary operation on the set SS of all nonzero real numbers as follows: for any a,a, b∈S,b\in S, a∗b=2ab.a*b=2ab. Which statement is not true?
∗* is commutative over SS
∗* is associative over SS
12\frac{1}{2} is an identity element for ∗* in SS
Every element of SS has an inverse for ∗*
12a\frac{1}{2a} is an inverse for ∗* of the element aa of SS
Answer: E
Concepts:custom operationalgebraic manipulation
Small hint:
First determine the identity ee from a∗e=aa*e=a
Big hint:
An inverse xx of aa must satisfy a∗x=12a*x=\frac{1}{2}
Solution:
The operation is commutative, and (a∗b)∗c=4abc=a∗(b∗c), (a*b)*c=4abc=a*(b*c), so it is associative. Its identity is 12.\frac{1}{2}. The inverse of aa must satisfy 2ax=12,2ax=\frac{1}{2}, so it is x=14a,x=\frac{1}{4a}, not 12a.\frac{1}{2a}.
Therefore, the correct answer is E.
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