1974 AMC 12 Problem 15

Attempt Problem 15 of the 1974 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1974 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

15.

If x<−2x\lt-2 then ∣1−∣1+x∣∣\bigl|1-|1+x|\bigr| equals
2+x2+x
−2−x-2-x
xx
−x-x
−2-2
Answer: B
Concepts:absolute valueinequality
Small hint:
Resolve the inner absolute value first using 1+x<−11+x\lt-1
Big hint:
After replacing ∣1+x∣|1+x| by −1−x,-1-x, determine the sign of 2+x2+x
Solution:
Since x<−2,x\lt-2, 1+x<0,1+x\lt0, so ∣1+x∣=−1−x.|1+x|=-1-x. Thus ∣1−∣1+x∣∣\bigl|1-|1+x|\bigr| becomes ∣1−(−1−x)∣,|1-(-1-x)|, which is ∣2+x∣=−2−x|2+x|=-2-x because 2+x<0.2+x\lt0.
Therefore, the correct answer is B.
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