1974 AMC 12 Problem 21

Attempt Problem 21 of the 1974 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1974 AMC 12 solutions, or check the answer key.

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21.

In a geometric series of positive terms the difference between the fifth and fourth terms is 576,576, and the difference between the second and first terms is 9.9. What is the sum of the first five terms of this series?
10611061
10231023
10241024
768768
none of these
Answer: B
Concepts:geometric sequencesummation
Small hint:
Write the first term as aa and the common ratio as rr
Big hint:
Divide ar3(r−1)=576ar^3(r-1)=576 by a(r−1)=9a(r-1)=9
Solution:
Let the first term be aa and the ratio be r.r. The conditions give ar3(r−1)=576,a(r−1)=9. \begin{aligned} ar^3(r-1)&=576,\\ a(r-1)&=9. \end{aligned} Their quotient gives r3=64,r^3=64, so r=4.r=4. Then 3a=9,3a=9, hence a=3.a=3. The sum is S=3(1+4+16+64+256)=3⋅341=1023. \begin{aligned} S&=3(1+4+16+64+256)\\ &=3\cdot341\\ &=1023. \end{aligned}
Therefore, the correct answer is B.
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