1977 AMC 12 Problem 21

Attempt Problem 21 of the 1977 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1977 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

21.

For how many values of the coefficient aa do the equations x2+ax+1=0,x2−x−a=0 \begin{aligned} x^2+ax+1&=0,\\ x^2-x-a&=0 \end{aligned} have a common real solution?
00
11
22
33
infinitely many
Answer: B
Concepts:quadraticsystem of equationsfactoring
Small hint:
Subtract the two equations to obtain a factored condition
Big hint:
Check separately the cases a=−1a=-1 and x=−1x=-1
Solution:
Subtracting the second equation from the first gives (a+1)x+(a+1)=(a+1)(x+1)=0. \begin{gathered} (a+1)x+(a+1)\\ =(a+1)(x+1)=0. \end{gathered} If a=−1,a=-1, the common equation is x2−x+1=0,x^2-x+1=0, which has no real roots. Otherwise x=−1,x=-1, and substitution into x2−x−a=0x^2-x-a=0 gives a=2.a=2. This value works, so exactly one value of aa qualifies.
Therefore, the correct answer is B.
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.