1976 AMC 12 Problem 14

Attempt Problem 14 of the 1976 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1976 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

14.

The measures of the interior angles of a convex polygon are in arithmetic progression. If the smallest angle is 100∘100^\circ and the largest angle is 140∘,140^\circ, then the number of sides the polygon has is
66
88
1010
1111
1212
Answer: A
Concepts:angle sumarithmetic sequencelinear equation
Small hint:
The average of an arithmetic progression is the average of its first and last terms
Big hint:
Equate 120n120n with the interior-angle sum 180(n−2)180(n-2)
Solution:
The average angle is 100+1402=120∘,\frac{100+140}{2}=120^\circ, so the angle sum is 120n.120n. A convex nn-gon has angle sum 180(n−2),180(n-2), hence 120n=180(n−2)120n=180(n-2) and n=6.n=6.
Therefore, the correct answer is A.
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