1979 AMC 12 Problem 22

Attempt Problem 22 of the 1979 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1979 AMC 12 solutions, or check the answer key.

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22.

Find the number of pairs (m,n)(m,n) of integers which satisfy the equation m3+6m2+5m=27n3+9n2+9n+1. \begin{aligned} m^3+6m^2+5m &=27n^3+9n^2\\ &\quad+9n+1. \end{aligned}
00
11
33
99
infinitely many
Answer: A
Concepts:divisibilitymodular arithmeticfactoring
Small hint:
Factor the left side as m(m+1)(m+5)m(m+1)(m+5)
Big hint:
Compare the two sides modulo 33
Solution:
The left side is m(m+1)(m+5)=m(m+1)(m+2)+3m(m+1), \begin{gathered} m(m+1)(m+5)\\ =m(m+1)(m+2)\\ \quad+3m(m+1), \end{gathered} which is divisible by 33 for every integer m.m. The right side is 3(9n3+3n2+3n)+1,3(9n^3+3n^2+3n)+1, which is congruent to 1(mod3).1\pmod3. Therefore no integer pair satisfies the equation.
Therefore, the correct answer is A.
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