1980 AMC 12 Problem 30

Attempt Problem 30 of the 1980 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1980 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

30.

A six digit number (base 1010) is squarish if it satisfies the following conditions:
(i) none of its digits is zero;
(ii) it is a perfect square; and
(iii) the first two digits, the middle two digits and the last two digits of the number are all perfect squares when considered as two digit numbers.
How many squarish numbers are there?
00
22
33
88
99
Answer: B
Concepts:digitsperfect squaresystematic listing
Small hint:
List the two-digit perfect squares having no zero digit
Big hint:
Use the first pair to restrict the square root to a short interval, then filter by the final pair
Solution:
Each two-digit block must belong to {16,25,36,49,64,81}. \{16,25,36,49,64,81\}. Restricting the square root by the first block and retaining only squares with an allowed final block leaves the following possible middle blocks:
first block possible middle blocks
1616 32,32, 40,40, 48,48, 56,56, 64,64, 7272
2525 40,40, 50,50, 60,60, 70,70, 80,80, 9090
3636 48,48, 60,60, 72,72, 84,84, 9696
4949 56,56, 70,70, 84,84, 9898
6464 64,64, 80,80, 9696
8181 72,72, 9090
Only the middle block 6464 is allowed, producing 166464=4082,646416=8042. \begin{aligned} 166464&=408^2,\\ 646416&=804^2. \end{aligned} Thus there are 22 squarish numbers.
Therefore, the correct answer is B.
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