1981 AMC 12 Problem 20

Attempt Problem 20 of the 1981 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1981 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

20.

A ray of light originates from point AA and travels in a plane, being reflected nn times between lines ADAD and CD,CD, before striking a point BB (which may be on ADAD or CDCD) perpendicularly and retracing its path to A.A. (At each point of reflection the light makes two equal angles as indicated in the adjoining figure. The figure shows the light path for n=3.n=3.) If ∠CDA=8∘,\angle CDA=8^\circ, what is the largest value nn can have?
66
1010
3838
9898
There is no largest value.
Answer: B
Concepts:reflection (geometry)angle chasinginequality
Small hint:
Track the acute angle between the ray and each successive reflecting line
Big hint:
Each reflection advances that angle by the wedge angle 8∘8^\circ
Solution:
Let θ>0\theta\gt0 be the initial acute angle between the ray and AD.AD. Successive exterior-angle relations increase the corresponding acute angle by 8∘8^\circ at each reflection. At the final perpendicular strike, 90∘=θ+(8n+8)∘. 90^\circ=\theta+(8n+8)^\circ. Thus θ=82∘−8n∘>0,\theta=82^\circ-8n^\circ\gt0, so n<828=10.25.n\lt\frac{82}{8}=10.25. The greatest integer possible is 10,10, attained when θ=2∘.\theta=2^\circ.
Therefore, the correct answer is B.
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