1984 AMC 12 Problem 28

Attempt Problem 28 of the 1984 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1984 AMC 12 solutions, or check the answer key.

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28.

The number of distinct pairs of integers (x,y)(x,y) such that 0<x<y,1984=x+y \begin{aligned} 0&\lt x\lt y,\\ \sqrt{1984}&=\sqrt{x}+\sqrt{y} \end{aligned} is
00
11
22
33
77
Answer: D
Concepts:radicalperfect squarecounting pairs
Small hint:
Use 1984=31⋅821984=31\cdot8^2 and write both radicands with a common squarefree part
Big hint:
Set x=31u2, y=31v2x=31u^2,\ y=31v^2 and count positive integers u<vu\lt v with u+v=8u+v=8
Solution:
Because x+y=831,\sqrt{x}+\sqrt{y}=8\sqrt{31}, the two radicals must have common squarefree part 31.31. Write x=31u2x=31u^2 and y=31v2y=31v^2 for positive integers u,v.u,v. Then u+v=8,u<v. u+v=8,\qquad u\lt v. The possibilities are (u,v)=(1,7),(u,v)=(1,7), (2,6),(2,6), and (3,5),(3,5), producing three distinct pairs (x,y).(x,y).
Therefore, the correct answer is D.
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