1985 AMC 12 Problem 17

Attempt Problem 17 of the 1985 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1985 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

17.

Diagonal DBDB of rectangle ABCDABCD is divided into three segments of length 11 by parallel lines LL and L′L' that pass through AA and CC and are perpendicular to DB.DB. The area of ABCD,ABCD, rounded to one decimal place, is
4.14.1
4.24.2
4.34.3
4.44.4
4.54.5
Answer: B
Concepts:areadiagonalrectanglevector
Small hint:
Let the rectangle’s side lengths be w,h;w,h; then its diagonal has length 33
Big hint:
Project the vertical and horizontal sides onto the diagonal to obtain h23=1\frac{h^2}{3}=1 and w23=2\frac{w^2}{3}=2
Solution:
Let D=(0,0),D=(0,0), B=(w,h),B=(w,h), A=(0,h)A=(0,h) and C=(w,0).C=(w,0). Since DB=3,DB=3, we have w2+h2=9.w^2+h^2=9. The projection of DADA onto DBDB has length h23,\frac{h^2}{3}, and the first marked segment has length 1,1, so h2=3.h^2=3. Similarly, the projection of DCDC reaches the second division point, so w23=2\frac{w^2}{3}=2 and w2=6.w^2=6. Hence the area is wh=18=32≈4.2426, wh=\sqrt{18}=3\sqrt2\approx4.2426, which rounds to 4.2.4.2.
Therefore the correct answer is B.
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