1985 AMC 12 Problem 4

Attempt Problem 4 of the 1985 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1985 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

4.

A large bag of coins contains pennies, dimes and quarters. There are twice as many dimes as pennies and three times as many quarters as dimes. An amount of money which could be in the bag is
$306\$306
$333\$333
$342\$342
$348\$348
$360\$360
Answer: C
Concepts:divisibilitymoneyratio and proportion
Small hint:
Let the number of pennies be pp
Big hint:
Express the total value in cents as a multiple of pp
Solution:
If there are pp pennies, there are 2p2p dimes and 6p6p quarters. Their total value is p+10(2p)+25(6p)=171pp+10(2p)+25(6p)=171p cents. Of the listed dollar amounts, 34200=171⋅20034200=171\cdot200 cents is possible.
Thus the correct answer is C.
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.