1952 AMC 12 Problem 10

Attempt Problem 10 of the 1952 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1952 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

10.

An automobile went up a hill at a speed of 1010 miles an hour and down the same distance at a speed of 2020 miles an hour. The average speed for the round trip was:
121212\dfrac12 mph
131313\dfrac13 mph
141214\dfrac12 mph
1515 mph
None of these
Answer: B
Concepts:distance rate and timeharmonic mean
Small hint:
Use equal distances rather than averaging the two speeds directly
Big hint:
For a one-mile trip each way, divide the total distance 22 by the total time 110+120\frac{1}{10}+\frac{1}{20}
Solution:
For one mile in each direction, the total time is 110+120=320 \frac1{10}+\frac1{20}=\frac3{20} hour. Thus the average speed is 2320=403=1313 mph. \frac{2}{\frac{3}{20}}=\frac{40}{3} =13\frac13\text{ mph}.
Thus, the correct answer is B.
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