1955 AMC 12 Problem 15

Attempt Problem 15 of the 1955 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1955 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

15.

The ratio of the areas of two concentric circles is 1:3.1:3. If the radius of the smaller is r,r, then the difference between the radii is best approximated by:
0.41r0.41r
0.730.73
0.750.75
0.73r0.73r
0.75r0.75r
Answer: D
Concepts:circle arearatioapproximation
Small hint:
Area ratios are the squares of radius ratios
Big hint:
The larger radius is r3r\sqrt3, so estimate 3−1\sqrt3-1
Solution:
If the larger radius is R,R, then πr2πR2=13, \frac{\pi r^2}{\pi R^2}=\frac13, so R=r3.R=r\sqrt3. The difference is R−r=(3−1)r≈0.732r. R-r=(\sqrt3-1)r\approx0.732r.
Thus, the best approximation is 0.73r,0.73r, and the correct answer is D.
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